Favour Onwuchekwa

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Favour provided a contribution 6 months ago

Question 2356 | English Language Past Questions

Option A is the only correctly spelt option.

Favour provided a contribution 6 months ago

Question 1447 | English Language Past Questions

The correct answer should be Option C.
The statement "That's the much many consumers know" means that the aforementioned uses of Vegetables are the only uses that consumers are aware about. That's why in the proceeding Paragraphs, the writer melted out other Uses of the \( Pumpkin Leaf \) [ Vegetables].

Favour provided a contribution 6 months ago

Question 1558 | English Language Past Questions

Option B- Common language is correct.

Favour provided a contribution 6 months ago

Question 1161 | English Language Past Questions

Option A is correct. Joys rhymes with Boys.

Favour provided a contribution 6 months ago

Question 1987 | Chemistry Past Questions

Initial Pressure [\( P_1 \)] = 800mmHg
Final Pressure [\( P_2 \)] = 650mmHg
Initial Volume [\( V_1 \)] = \( 300cm^3 \)
Final Volume = [\( V_2 \)]
Using Boyle's Law;
\( P_1V_1 = P_2V_2 \)
800 × 300 = 650 × \( V_2 \)
650\( V_2 \) = 240,000
\( V_2 = \frac{240,000}{650} \)
\( V_2 = 369.23cm^3 \)

Favour provided a contribution 6 months ago

Question 1972 | Chemistry Past Questions

The equation for the reaction is;
HCL + NaOH \( \rightarrow \) NaCl + \( H_2O \)
Concentration of Acid [\( C_a \)] = 0.05\( moldm^{–3} \)
Concentration of Base = [\( C_b \)]
Volume of Acid[\( V_a \)] = 32\( cm^3 \)
Volume of Base[\( V_b \)] = 25\( cm^3 \)
number of moles of Acid [\( _nA \) = 1
number of moles of Base[\( _nB \)] = 1
Using the formula:
\( \frac{C_a V_a}{C_bV_b} = \frac{_nA}{_nB} \)
we have;
\( \frac{0.05 × 32}{C_b × 25} = \frac{1}{1} \)
\( C_b × 25 = 1.6 \)
\( C_b = \frac{1.6}{25} \)
\( C_b = 0.064 \)
\( \therefore \) The concentration of Base is 0.064\( moldm^{–3} \)

Favour provided a contribution 6 months ago

Question 1952 | Chemistry Past Questions

Molecular mass of the hydrocarbon [X] = 26
Percentage of carbon = 92.3%
Percentage of Hydrogen = 100% – 92.3% = 7.7%
[C=12, H=1]
C H
\( \downarrow \) \( \downarrow \)
\( \frac{92.3}{12} \) \( \frac{7.7}{1} \)
7.7 7.7
Divide through by the smallest number
\( \frac{7.7}{7.7} \) \( \frac{7.7}{7.7} \)
1 1
\( \therefore \) The empirical formula is [CH]
Recall that the Molecular mass is 26.
So;
\( [CH]_n \) = 26
\( [12+1]_n \) = 26
13n = 26
n = \( \frac{26}{13} \)
n = 2
Molecular Formula = \( [CH]_2 \)
\( \therefore \) Molecular Formula = \( C_2H_2 \).

Favour provided a contribution 6 months ago

Question 1947 | Chemistry Past Questions

Polyvinyl chloride [P. V. C] is used in the production of \( pipes \).

Favour provided a contribution 6 months ago

Question 2134 | Physics Past Questions

Electromotive force[E.m.f] = 12V
Current= [I]
External Resistance [R] = 2\(\Omega \)
Internal Resistance [r] = 4\(\Omega \)
Recall;
E = I [ R+ r]
12 = I [2+4]
12 = 6I
I = \( \frac{12}{6} \)
I = 2A
\( \therefore The current is 2A \)

Favour provided a contribution 6 months ago

Question 1587 | Biology Past Questions

Point of correction!!
Not all living organisms can undergo "Sexual Reproduction". Some plants undergo asexual reproduction.
The appropriate answer should be option D- The ability to remove unwanted substances.

Favour provided a contribution 6 months ago

Question 2210 | English Language Past Questions

Option D is correct.
\( sighted \) best fills the gap.

Favour provided a contribution 6 months ago

Question 2053 | Physics Past Questions

Velocity [V] \( \alpha \)\( \sqrt{Temperature[T]} \)
V = K\( \sqrt{T} \)
K = \( \frac{V}{\sqrt{T}} \)
The equation would be written as;
\( \frac{V_1}{\sqrt{T_1}} = \frac{V_2}{\sqrt{T_2}} \)
Initial velocity = [\( V_1 \)]
Final velocity = [\( V_2 \)] = 340\( ms^{–1} \)
Initial Temperature [\( T_1 \)] = 100°c = 373K
Final Temperature[\( T_2 \)] = 0°c = 273K
\( \frac{V_1}{\sqrt{373}} = \frac{340}{\sqrt{273}} \)
\( \frac{V_1}{\sqrt{373}} = 20.58 \)
\( V_1 \) = 20.58\( \sqrt{373} \)
\( V_1 \) = 397.47
\( V_1 = 397ms^{–1} \)

Favour provided a contribution 6 months ago

Question 1393 | Biology Past Questions

The adaptive importance of nuptial flight from termite Colonies is to disperse the reproductives for the purpose of establishing New Colonies.

Favour provided a contribution 6 months ago

Question 1192 | Biology Past Questions

I totally disagree. Option B is wrong. The question is about the economic Impoortance of the organism and not the "Disadvantage".
Option D is the appropriate answer.

Favour provided a contribution 6 months ago

Question 2111 | Physics Past Questions

No option is correct.
The equivalent of 20K In Celcius scale is;
20K – 273K = –253°c✔️✔️

Favour provided a contribution 6 months ago

Question 1310 | Biology Past Questions

"Xerophytes" are plants that grow in very dry areas. They increase their water conservation by reducing their leaves to \( spines \).

Favour provided a contribution 6 months ago

Question 1309 | Biology Past Questions

The correct answer is "A" -Quill feather.

Favour provided a contribution 6 months ago

Question 1273 | Biology Past Questions

Blood group AB is generally referred to as "Universal Recipient".

Favour provided a contribution 6 months ago

Question 1456 | Biology Past Questions

The correct answer is option C - Population Ecology

Favour provided a contribution 6 months ago

Question 1134 | Physics Past Questions

The Question was wrongly set.
\( Osmosis \)
Osmosis can be defined as the movement of water molecules from a region of dilute/ weaker solution to a region of concentrated / stronger solution through a selectively/ differentially permeable membrane.
\( Diffusion \)
Diffusion on the other hand is defined as the process by which molecules or ions of a substance move from a region of high concentration to a region of low concentration until they are evenly distributed.
NB: Osmosis is similar to Diffusion so their definitions should not be mistaken.

Favour provided a contribution 6 months ago

Question 1128 | Physics Past Questions

Efficiency of a Transformer = \( \frac{Power developed in the secondary coil}{Power supplied to the primary coil} × 100% \)

Favour provided a contribution 6 months ago

Question 922 | Physics Past Questions

I strongly disagree with you on that anwer.
Half life = \( t_{\frac{1}{2}} \)
Decay constant [\( \lambda \)] = \( 10^{–6}s^{–1} \)
Half life =
\( \frac{0.693}{\lambda} \)
Half life = \( \frac{0.693}{10^{–6}} \)
Half life = 0.693 × \( \frac{1}{10^{–6}} \)
Half life = 0.693 × \( 10^6 \)
Half life = \( 6.93 × 10^5 \)
No option is correct.

Favour provided a contribution 6 months ago

Question 914 | Physics Past Questions

Pressure [P] = \( 7.6 × 10^6 \)\(Nm^{-2} \)
Volume [V] = \( 10^{–3}m^3 \)
nō of moles [n] = 6moles
Gas constant [R] = \( 8.3jmol^{–1}K^{–1} \)
Temperature = [T]
Using the formula;
PV = nRT
T = \( \frac{PV}{nR} \)
T = \( \frac{7.6×10^6 × 10^{–3}}{6 × 8.3} \)
T = \( \frac{7600}{49.8} \)
\( \therefore T = 152.6°c ≈ 153°c \)
Option "C" is correct. Thanks.

Favour provided a contribution 6 months ago

Question 909 | Physics Past Questions

Refractive Index[n] = 1.33
Real depth = ?
Apparent depth = 1m
Recall:
n = \( \frac{Real depth}{Apparent depth} \)
1.33 = \( \frac{Real depth}{1} \)
\( \therefore \) Real depth = 1.33m
Option "D" is 💯% correct.

Favour provided a contribution 6 months ago

Question 904 | Physics Past Questions

D - Centripetal and Centrifugal Firces

Favour provided a contribution 6 months ago

Question 899 | Physics Past Questions

Magnification[M] = 3
Image distance = V
Object distance [U] = 10cm
Focal length = [F]
Recall;
M = \( \frac{V}{U} \)
3 = \( \frac{V}{10} \)
V = 30cm
The image formed is a Virtual Image; So, V = –30cm
Using the mirror formula;
\( \frac{1}{F} = \frac{1}{U} + \frac{1}{V} \)
\( \frac{1}{F} = \frac{1}{10} + \frac{1}{–30} \)
\( \frac{1}{F} = \frac{1}{10} –\frac{1}{30} \)
\( \frac{1}{F} = \frac{3–1}{30} \)
\( \frac{1}{F} = \frac{2}{30} \)
\( \therefore F = 15 \)cm
option "D" is 💯% correct.

Favour provided a contribution 6 months ago

Question 898 | Physics Past Questions

Boiling occurs when the vapour pressure of a liquid equals the Atmospheric pressure.

Favour provided a contribution 6 months ago

Question 896 | Physics Past Questions

Frequency of Beat = ?
Frequency of the \( 1^{st} \) tuning fork[\( F_1 \)] = 258Hz
Frequency of the \( 2^{nd} \) tuning fork [\( F_2 \)] = 270Hz
Frequency of Beat = \( F_2 – F_1 \)
Frequency of Beat = 270Hz–258Hz
\( \therefore Frequency of Beat = 12Hz \)
option "D" is 💯% correct.

Favour provided a contribution 6 months ago

Question 895 | Physics Past Questions

Option "D" is 💯% correct because Atoms of elements can never be the same / identical.

Favour provided a contribution 6 months ago

Question 894 | Physics Past Questions

The direction of the Force between N and S in the magnetic field will be "NS" as the direction of the arrow implies.
option " C" is 100% correct.

Favour provided a contribution 6 months ago

Question 1161 | Biology Past Questions

The order of classification of living things is as follows:
Kingdom
|
Phylum/Division
|
Class
|
Order
|
Family
|
Genus
|
Species
\( \therefore \) Species is the lowest unit of classification of Living things.

Favour provided a contribution 6 months ago

Question 1170 | Biology Past Questions

A "Tissue" is a collection of a group of similar cells that perform similar functions.

Favour provided a contribution 6 months ago

Question 1151 | Biology Past Questions

The correct answer is A. Adrenal gland is located at the top of the Kidney.

Favour provided a contribution 6 months ago

Question 1144 | Biology Past Questions

The primary consumer in a food Chain feeds directly on the "Producers" [Green plants].
Option [ A] is 💯% correct.

Favour provided a contribution 6 months ago

Question 1136 | Biology Past Questions

Adrenaline is generally referred to as the " Emergency hormone". It is located at the top of the " Kidney".

Favour provided a contribution 6 months ago

Question 911 | English Language Past Questions

Point of correction "Timid" is the opposite of "Daring" and not the nearest in meaning.

Favour provided a contribution 6 months ago

Question 4761 | Physics Past Questions

Time [t] = 0.8 seconds
Speed of sound in air[V]= 340\( ms^{-1} \)
Distance= x
\( V= \frac{2x}{t} \)
\( 340 = \frac{2x}{0.8} \)
2x = 340× 0.8
2x = 272
x = \( \frac{272}{2} \)
x = 136m
Option [B] is 💯% correct.

Favour provided a contribution 6 months ago

Question 4759 | Physics Past Questions

Voltage [V] = 12v
Current [I] = 2A
Time [T] = 5minutes = 300seconds
Recall from ohm's law;
V = IR
12 = 2R
R = \( \frac{12}{2} \)
R = 6\( \Omega \)
Energy [E] = \( I^2RT \)
Energy [E] = \( 2^2 × 6 × 300 \)
Energy [E] = 7200J
Option [C] is 💯% correct.

Favour provided a contribution 6 months ago

Question 4755 | Physics Past Questions

I disagree to agree with you on that answer.
Focal length [F] = 20cm
Image distance [V] = 100cm
Object distance = U
Using the mirror formula;
\( \frac{1}{F} = \frac{1}{U} + \frac{1}{V} \)
\( \frac{1}{20} = \frac{1}{U} + \frac{1}{100} \)
\( \frac{1}{U} = \frac{1}{20} – \frac{1}{100} \)
\( \frac{1}{U} = \frac{1}{25} \)
\( \therefore U = 25cm \)
Option [C] is 100% correct. Thanks.

Favour provided a contribution 6 months ago