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A rectangular block of wood floats in water with two-thirds of its volume immers...


Question

A rectangular block of wood floats in water with two-thirds of its volume immersed. When placed in another liquid, it floats with half of its volume immersed. Calculate the relative density of the liquid

Options

A) 1.43

B) 1.33

C) 1.00

D) 0.83

E) 0.75


The correct answer is E.

Explanation:

R.D = \(\frac{\text{volume of liquid displaced}}{\text{volume of water displaced}}\)
= \(\frac{1}{2} - \frac{2}{3} = \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}\)
= 0.75


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Dicussion (1)

  • R.D = \(\frac{\text{volume of liquid displaced}}{\text{volume of water displaced}}\)
    = \(\frac{1}{2} - \frac{2}{3} = \frac{1}{2} \times \frac{3}{2} = \frac{3}{4}\)
    = 0.75

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