A gas at pressure PN-m-2 and temperature 27°C is heated to 77°C at constant vo...
Question
A gas at pressure PN-m-2 and temperature 27°C is heated to 77°C at constant volume. The new pressure is
Options
A)
0.85 PN-m-2
B)
0.86 PN-m-2
C)
1.16 PN-m-2

D)
1.18 PN-m-2
E)
2.85 PN-m-2
Related Lesson: Summarizing Gauge Pressure and Absolute Pressure | Fluid Statics
The correct answer is C.
Explanation:
At constant volume,
\(\frac{P_1}{T_1}\) = \(\frac{P_2}{T_2}\)
\(\frac{P_1}{27 +273}\) = \(\frac{27}{27 + 273}\)
P2 = 1.16 PN-m-2
More Past Questions:
Discussion (2)
Other Subjects
- English Language
- Biology
- Mathematics
- Government
- Economics
- Chemistry
- Christian Religious Knowledge
- Commerce
- Geography
- Literature In English
- Accounts
- Agricultural Science
- General Paper
- Islamic Religious Knowledge
- History
- Further Mathematics
- Current Affairs
- Computer Studies
- Civic Education
- Math
- Reading
- Writing and Language
- Home Economics
- Igbo
- Hausa
- Yoruba
- French
- Fine Arts
The solution is authomagically wrong
The question is from charle's laws
At constants volume.P1/T1=P2/T2
P1/27+273=P2/77+273
P1/300=P2/350
Cross multiply
300P2=350p
Divide both side by coefficient P2
350p/300p2
P2=1.16PN-m²
At constant volume,
\(\frac{P_1}{T_1}\) = \(\frac{P_2}{T_2}\)
\(\frac{P_1}{27 +273}\) = \(\frac{27}{27 + 273}\)
P2 = 1.16 PN-m-2