The latent heat of fusion of ice is 80cal g-1. How much heat is required to chan...
Question
The latent heat of fusion of ice is 80cal g-1. How much heat is required to change 10g of ice at Q°C into water at the same temperature?
Options
A)
80 cal
B)
10 cal
C)
8 cal
D)
800 cal
E)
400 cal
Related Lesson: Temperature Change and Heat Capacity | Heat and Heat Transfer Methods
The correct answer is D.
Explanation:
Quantity of heat = ml
= 10 × 80
= 800 cal
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Quantity of heat = ml
= 10 × 80
= 800 cal