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# Calculate the apparent weight loss of a man weighing 70kg in an elevator moving ...

### Question

Calculate the apparent weight loss of a man weighing 70kg in an elevator moving downwards with an acceleration of 1.5ms-2.

A)
105N
B)
686N
C)
595N
D)
581N

### Explanation:

The apparent weight of the man when the lift moves downward is:
$$W = M(g - a)$$
$$= 70(10 - 1.5)$$
$$= 70 \times 8.5 = 595\text{N}$$

Explanation provided by John Kenny Ade

## Discussion (5)

• Joseph

M(g-a)
70 x 10-1.5
595

• Mike Unachi

The correct answer is A. 105 N.
595 N is the apparent weight of the man. The question requires the apparent weight loss.
i.e. (70 x 10) - 595 = 105 N.

• The answer is C becos what is asked is the apparent weight on an elevator moving downward

• The apparent weight of the man when the lift moves downward is:
$$W = M(g - a)$$
$$= 70(10 - 1.5)$$
$$= 70 \times 8.5 = 595\text{N}$$
Given: $$w = 70\text{kg}$$, $$a = 1.5\text{m/s}^2$$
when $$m = w$$
$$F = ma$$
$$F = 70 \times 1.5 = 105\text{N}$$