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Calculate the apparent weight loss of a man weighing 70kg in an elevator moving ...


Question

Calculate the apparent weight loss of a man weighing 70kg in an elevator moving downwards with an acceleration of 1.5ms-2.

Options

A)
105N
B)
686N
C)
595N
D)
581N

The correct answer is C.

Explanation:

The apparent weight of the man when the lift moves downward is:
\(W = M(g - a)\)
\(= 70(10 - 1.5)\)
\(= 70 \times 8.5 = 595\text{N}\)
Therefore the answer is C.

Explanation provided by John Kenny Ade


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Discussion (5)

  • Joseph

    M(g-a)
    70 x 10-1.5
    595

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  • Mike Unachi

    The correct answer is A. 105 N.
    595 N is the apparent weight of the man. The question requires the apparent weight loss.
    i.e. (70 x 10) - 595 = 105 N.

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  • The answer is C becos what is asked is the apparent weight on an elevator moving downward

  • The apparent weight of the man when the lift moves downward is:
    \(W = M(g - a)\)
    \(= 70(10 - 1.5)\)
    \(= 70 \times 8.5 = 595\text{N}\)
    Therefore the answer is C.

  • Ayomide

    Given: \(w = 70\text{kg}\), \(a = 1.5\text{m/s}^2\)
    when \(m = w\)
    \(F = ma\)
    \(F = 70 \times 1.5 = 105\text{N}\)

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