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1kg of boiling water at 100°C is poured into an aluminium hot water bottle at 1...


Question

1kg of boiling water at 100°C is poured into an aluminium hot water bottle at 16°C. The temperature of the water quickly falls to 96°C. Assuming that there is no loss of heat, the mass of the bottle is

Options

A) 0.25kg

B) 0.5kg

C) 0.05kg

D) 0.75kg.

The correct answer is A.

Explanation:

100° mcΔΘ : 96°
m=1kg Co=4200J/Kgk
Θ=100°
Q=mcΔΘ=1 × 4200 × (100-96)
=4200 × 4
=16800J
For aluminium bottle
m= C=900J/Kgk Θ=16°
Q=mcΔΘ=m × 840 × (96-16)
=m × 840 × 80
=67200m
Heat gain = Heat loss
16800=67200m
m=16800/67200
=0.25kg


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Dicussion (1)

  • 100° mcΔΘ : 96°
    m=1kg Co=4200J/Kgk
    Θ=100°
    Q=mcΔΘ=1 × 4200 × (100-96)
    =4200 × 4
    =16800J
    For aluminium bottle
    m= C=900J/Kgk Θ=16°
    Q=mcΔΘ=m × 840 × (96-16)
    =m × 840 × 80
    =67200m
    Heat gain = Heat loss
    16800=67200m
    m=16800/67200
    =0.25kg

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