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A \(10\mu \mathrm{C}\) charge moves with a velocity of \(1.0 \times 10^5 ms^{-1}\)...


Question

A \(10\mu \mathrm{C}\) charge moves with a velocity of \(1.0 \times 10^5 ms^{-1}\) at right angle to a uniform magnetic field of flux density \(5.0 \times 10^{-4}T.\) Calculate the force on the charge.

Options

A) \(5.0 \times 10^{-5} \mathrm{N}\)

B) \(5.0 \times 10^{-4} \mathrm{N}\)

C) \(5.0 \times 10^5 \mathrm{N}\)

D) \(5.0 \times 10^6 \mathrm{N}\)

Explanation:

\(F = qvB\)
\(= 10 \times 10^{-6} \times 1.0 \times 10^5 \times 10^{-4}\)
\(= 5.0 \times 10^{-4} \mathrm{N}\)


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