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# A $$10\mu \mathrm{C}$$ charge moves with a velocity of $$1.0 \times 10^5 ms^{-1}$$...

### Question

A $$10\mu \mathrm{C}$$ charge moves with a velocity of $$1.0 \times 10^5 ms^{-1}$$ at right angle to a uniform magnetic field of flux density $$5.0 \times 10^{-4}T.$$ Calculate the force on the charge.

### Options

A) $$5.0 \times 10^{-5} \mathrm{N}$$

B) $$5.0 \times 10^{-4} \mathrm{N}$$

C) $$5.0 \times 10^5 \mathrm{N}$$

D) $$5.0 \times 10^6 \mathrm{N}$$

### Explanation:

$$F = qvB$$
$$= 10 \times 10^{-6} \times 1.0 \times 10^5 \times 10^{-4}$$
$$= 5.0 \times 10^{-4} \mathrm{N}$$

## Dicussion (1)

• $$F = qvB$$
$$= 10 \times 10^{-6} \times 1.0 \times 10^5 \times 10^{-4}$$
$$= 5.0 \times 10^{-4} \mathrm{N}$$