A \(10\mu \mathrm{C}\) charge moves with a velocity of \(1.0 \times 10^5 ms^{-1}\) at right angle to a uniform magnetic field of flux density \(5.0 \times 10^{-4}...
Question
A \(10\mu \mathrm{C}\) charge moves with a velocity of \(1.0 \times 10^5 ms^{-1}\) at right angle to a uniform magnetic field of flux density \(5.0 \times 10^{-4}T.\) Calculate the force on the charge.
Options
A)
\(5.0 \times 10^{-5} \mathrm{N}\)
B)
\(5.0 \times 10^{-4} \mathrm{N}\)
C)
\(5.0 \times 10^5 \mathrm{N}\)
D)
\(5.0 \times 10^6 \mathrm{N}\)
Related Lesson: Force On a Moving Charge in a Magnetic Field | Magnetism
The correct answer is B.
Explanation:
\(F = qvB\)
\(= 10 \times 10^{-6} \times 1.0 \times 10^5 \times 10^{-4}\)
\(= 5.0 \times 10^{-4} \mathrm{N}\)
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B is correct
B is correct
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\(F = qvB\)
\(= 10 \times 10^{-6} \times 1.0 \times 10^5 \times 10^{-4}\)
\(= 5.0 \times 10^{-4} \mathrm{N}\)