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The diagram shows a uniform meter rule AB which balances horizontally at the 90c...


Question

The diagram shows a uniform meter rule AB which balances horizontally at the 90cm mark when a mass of 0.2kg is suspended from B. Calculate the mass of the meter rule.

Options

A) 0.05kg

B) 0.20kg

C) 0.80kg

D) 1.00kg

The correct answer is A.

Explanation:

M\(_r\)(90 - 50) = 0.2(100 - 90)
40M\(_r\) = 0.2 × 10

M\(_r\) = \(\frac{2}{40}\) = 0.05kg

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