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# the shortest length of the air column in a resonance tube at resonance is 0.12m ...

### Question

the shortest length of the air column in a resonance tube at resonance is 0.12m and the next resonance length is 0.37m. calculate the frequency of vibration given that the speed of sound in air is 340m-1

### Options

A) 1360Hz

B) 694Hz

C) 680Hz

D) 34Hz

E) 340Hz

f = $$\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}$$ = 680
• f = $$\frac{v}{2(l_2 - l_1)} = \frac{340}{2(0.37 - 0.12)} = \frac{34}{0.5}$$ = 680