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A resistance thermometer has a resistance of 20\(\Omega\) at 0oC and 85\(\Omega\)...


Question

A resistance thermometer has a resistance of 20\(\Omega\) at 0oC and 85\(\Omega\) at 100oC. If its resistance is 52\(\Omega\)in a medium, calculate the corresponding temperature

Options

A) 49.2oC

B) 60.6oC

C) 80.0oC

D) 84.7oC

Explanation:

85\(\Omega\) ........100oC

52\(\Omega\) ........\(\theta\)oC

20\(\Omega\) ........0oC

\(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\)

\(\theta = \frac{32 \times 100}{65} = 49.2^oC\)


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Dicussion (1)

  • 85\(\Omega\) ........100oC

    52\(\Omega\) ........\(\theta\)oC

    20\(\Omega\) ........0oC

    \(\frac{52 - 20}{85 - 20} = \frac{\theta - 0}{100 - 0}\)

    \(\theta = \frac{32 \times 100}{65} = 49.2^oC\)

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