Nigerian Scholars » » Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[$$\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}$$...

# Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[$$\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}$$...

### Question

Two bodies each carrying a charge of 2.00 x 10-10C are 5cm apart. Calculate the magnitude of the force between the charges.[$$\frac{1}{4\pi \mathit{E}_o} = 9.00 \times 10^9 Nm^2C{-2}$$]

A) 1.44 x 10-7N

B) 7.20 x 10-9N

C) 7.20 x 10-11N

D) 1.44 x 1011N

### Explanation:

f = $$\frac{1}{4 \pi \mathit{E}_o} \times \frac{Q^2}{r^2} = \frac{9 \times 10^9(2 \times 10^{-2})^2}{(0.05)^2}$$

= 1.44 x 10-2N

## Dicussion (1)

• f = $$\frac{1}{4 \pi \mathit{E}_o} \times \frac{Q^2}{r^2} = \frac{9 \times 10^9(2 \times 10^{-2})^2}{(0.05)^2}$$

= 1.44 x 10-2N