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A body is projected with an initial velocity U at an angle O to the horizontal. ...


Question

A body is projected with an initial velocity U at an angle O to the horizontal. The time taken by it to reach its maximum height is given by the expression

Options

A) \(\frac{2u \text{sin}\theta}{g}\)

B) \(\frac{u^2 \text{sin}^2\theta}{2g}\)

C) \(\frac{u \text{sin}\theta}{g}\)

D) \(\frac{u \text{sin}\theta}{2g}\)


The correct answer is C.


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