An object of volume 400cm3 and 2.5gcm-3 is suspended from a spring balance with ...
Question
An object of volume 400cm3 and 2.5gcm-3 is suspended from a spring balance with half its volume immersed in water. Determine the reading on the spring balance. (Density of water = 1gcm-3)Options
A)
1200g
B)
1000g
C)
800g
D)
400g
Related Lesson: Potential Energy of a Spring | Work, Energy and Energy Resources
The correct answer is C.
Explanation:
Mass = density x volume
400 x 2.5 = 1000g
Loss in mass = volume x density
= \(\frac{400}{2}\) x 1 = 200g
Reading on spring balance = 1000 - 200g = 800g
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Mass = density x volume
400 x 2.5 = 1000g
Loss in mass = volume x density
= \(\frac{400}{2}\) x 1 = 200g
Reading on spring balance = 1000 - 200g = 800g