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An aluminium rod of length 1.8m at 100oC is heated to proceed pr...


Question

An aluminium rod of length 1.8m at 100oC is heated to proceed produce a difference in length of 0.007m. Calculate the temperature to which it is heated. (Linear expansivity of aluminium = 2.3 x 10-5K-1

Options

A) 155oC

B) 160oC

C) 169oC

D) 179oC

Explanation:

\(\alpha = \frac{L_2 - L_1}{L_1(\theta_2 - \theta_1)}\)

L2 - L1 = \(\alpha L_1 (\theta_2 - \theta_1)\)

\(\theta_2 = \frac{0.007}{2.3 \times 10^{-5} \times 1.8}\) + 10

= 179oC


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Dicussion (1)

  • \(\alpha = \frac{L_2 - L_1}{L_1(\theta_2 - \theta_1)}\)

    L2 - L1 = \(\alpha L_1 (\theta_2 - \theta_1)\)

    \(\theta_2 = \frac{0.007}{2.3 \times 10^{-5} \times 1.8}\) + 10

    = 179oC

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