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The lowest note emitted by a stretched string has a frequency of 40Hz. How many ...


Question

The lowest note emitted by a stretched string has a frequency of 40Hz. How many overtones are there between 40hz and 180Hz?

Options

A) 4

B) 3

C) 2

D) 1


The correct answer is B.

Explanation:

The lowest note (fundamental note) emitted by any stretched string has a fundamental frequecy fo = V/2l = 40Hz
The 1st overtone = 2fo = 2 x 40 = 80Hz
2nd overtone = 3fo = 3 x 40 = 120Hz
3rd overtone = 4fo = 4 x 40 = 160Hz
4th overtone = 5fo = 5 x 40 = 200Hz

Overtones between 40Hz and 180Hz are 80Hz, 120Hz, 160Hz = 3 Overtones


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Dicussion (1)

  • The lowest note (fundamental note) emitted by any stretched string has a fundamental frequecy fo = V/2l = 40Hz
    The 1st overtone = 2fo = 2 x 40 = 80Hz
    2nd overtone = 3fo = 3 x 40 = 120Hz
    3rd overtone = 4fo = 4 x 40 = 160Hz
    4th overtone = 5fo = 5 x 40 = 200Hz

    Overtones between 40Hz and 180Hz are 80Hz, 120Hz, 160Hz = 3 Overtones

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