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A piece of iron weights 250 N in air and 200 N in a liquid of density 1000 kgm-3...


Question

A piece of iron weights 250 N in air and 200 N in a liquid of density 1000 kgm-3. the volume of the iron is?

Options

A) 5.0 x 10-2 ms-2

B) 4.5 x 10--2 ms-3

C) 2.5 x 10-2 ms-8

D) 2.0 x 10-2 ms-3


The correct answer is C.

Explanation:

With in the air = 250N
wt. in the liquid = 200N
loss in wt. in the liquid = 250 - 200 = 50N
∴ Wt. the liquid of equal vol. of the iron = 50N
∴If the density of the liquid is 1000 lgm-3
then the volume of the liquid = (N)/D = V = (25kg)/1000 =0.025m3 = 2.5 x 10-2 m8.

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Dicussion (1)

  • With in the air = 250N
    wt. in the liquid = 200N
    loss in wt. in the liquid = 250 - 200 = 50N
    ∴ Wt. the liquid of equal vol. of the iron = 50N
    ∴If the density of the liquid is 1000 lgm-3
    then the volume of the liquid = (N)/D = V = (25kg)/1000 =0.025m3 = 2.5 x 10-2 m8.

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