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The pressure of one mole of an ideal gas of volume 10-2 m3 at a temperature of 27°...


Question

The pressure of one mole of an ideal gas of volume 10-2 m3 at a temperature of 27°c is
[molar gas constant = 8.3 J mol-1 k-1]

Options

A) 2.49 x 104 Nm-2

B) 2.24 x 104 Nm-2

C) 2.49 x 105 Nm-1

D) 2.24 x 105 Nm-1


The correct answer is C.

Explanation:

T = 27 + 273 = 300 K, volume, V = 10-2 m3 molar gass constant, R = 8.3 Jmol- 1k - 1 number of mole, n = 1
PV = NRT
i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
= 2.49 x 105 Nm-1

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Dicussion (1)

  • T = 27 + 273 = 300 K, volume, V = 10-2 m3 molar gass constant, R = 8.3 Jmol- 1k - 1 number of mole, n = 1
    PV = NRT
    i.e P = (NRT)/V = (1 x 8.3 x 300)/10-2
    = 2.49 x 105 Nm-1

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