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A machine is used to lift a load of 20 N through a height of 10 m. if the effici...


Question

A machine is used to lift a load of 20 N through a height of 10 m. if the efficiency of the machine is 40%, how much work is done?

Options

A)
80 J
B)
500 J
C)
300 J
D)
120 J

The correct answer is B.

Explanation:

Efficiency = \( \frac{\text{work output}}{\text{work input}} \times \frac{100}{1} \)

= 40 = \( \frac{20 \times 10 }{x} \times \frac{100}{1} \)
= 500J


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Dicussion (1)

  • Efficiency = \( \frac{\text{work output}}{\text{work input}} \times \frac{100}{1} \)

    = 40 = \( \frac{20 \times 10 }{x} \times \frac{100}{1} \)
    = 500J

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