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How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the i...

Question

How many grams of water at 17oC must be added to 42g of ice at 0oC to melt the ice completely? [specific latent heat of fusion of ice = 3.4 x 105Jkg-1, specific heat capacity of water = 4200Jkg-1k-1]

Options

A) 200g

B) 300g

C) 320g

D) 400g

The correct answer is A.

Explanation:

Heat lost = Heat gained

mc$$\theta$$ = mL

m x 4200 x 17 = 42 x 3.4 x 105

therefore, m = 200g

Dicussion (1)

• Heat lost = Heat gained

mc$$\theta$$ = mL

m x 4200 x 17 = 42 x 3.4 x 105

therefore, m = 200g