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# The energy contained in a wire when it extended by 0.02m by a force 500 N is

### Question

The energy contained in a wire when it extended by 0.02m by a force 500 N is

A) 5J

B) 10J

C) 103J

D) 104

### Explanation:

Energy = $$\frac{1}{2}$$Fe

= $$\frac{1}{2}$$ x 500 x 0.02

E = 5J

## Dicussion (1)

• Energy = $$\frac{1}{2}$$Fe

= $$\frac{1}{2}$$ x 500 x 0.02

E = 5J