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A cell of e.m.f 2V and internal resistance 1\(\Omega\) supplies a current of 0.5...


Question

A cell of e.m.f 2V and internal resistance 1\(\Omega\) supplies a current of 0.5 amps to a resistance whose value is

Options

A) 0.5\(\Omega\)

B) 1\(\Omega\)

C) 2\(\Omega\)

D) 2.5\(\Omega\)

E) 3\(\Omega\)


The correct answer is E.

Explanation:

1 = \(\frac{E}{R + r}\)

\(\frac{2}{R + 1}\) = 0.5

0.5R = 2 - 0.5 = 1.5

R = \(\frac{1.5}{0.5}\)

= 3\(\Omega\)


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