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A cell of e.m.f 2V and internal resistance 1$$\Omega$$ supplies a current of 0.5...

Question

A cell of e.m.f 2V and internal resistance 1$$\Omega$$ supplies a current of 0.5 amps to a resistance whose value is

Options

A) 0.5$$\Omega$$

B) 1$$\Omega$$

C) 2$$\Omega$$

D) 2.5$$\Omega$$

E) 3$$\Omega$$

Explanation:

1 = $$\frac{E}{R + r}$$

$$\frac{2}{R + 1}$$ = 0.5

0.5R = 2 - 0.5 = 1.5

R = $$\frac{1.5}{0.5}$$

= 3$$\Omega$$

Dicussion (1)

• 1 = $$\frac{E}{R + r}$$

$$\frac{2}{R + 1}$$ = 0.5

0.5R = 2 - 0.5 = 1.5

R = $$\frac{1.5}{0.5}$$

= 3$$\Omega$$