Home » Past Questions » Physics » A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of den...

A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of den...


Question

A solid weighs 4.8g in air, 2.8g in water and 3.2g in kerosine. The ratio of density of the solid to that of the kerosine is

Options

A) 12

B) 3

C) 2

D) \(\frac{3}{2}\)

E) \(\frac{5}{4}\)


The correct answer is B.

Explanation:

Relative density of solid = \(\frac{\text{weight of solid}}{\text{weight of an equal volume of water}}\)

\(\frac{4.8}{4.8 -3.2}\) = \(\frac{4.8}{2}\) = 2.4

Ratio of density of liquid = \(\frac{\text{weight of liquid kerosine}}{\text{weight of an equal volume of water}}\)

= \(\frac{4.8 - 3.2}{4.8 - 2.8}\) = \(\frac{1.6}{2}\)

= 0.8

= \(\frac{\text{density of solid}}{\text{density of kerosine}}\)

= \(\frac{2.4}{0.8}\) = 3


More Past Questions:


Dicussion (1)

  • Relative density of solid = \(\frac{\text{weight of solid}}{\text{weight of an equal volume of water}}\)

    \(\frac{4.8}{4.8 -3.2}\) = \(\frac{4.8}{2}\) = 2.4

    Ratio of density of liquid = \(\frac{\text{weight of liquid kerosine}}{\text{weight of an equal volume of water}}\)

    = \(\frac{4.8 - 3.2}{4.8 - 2.8}\) = \(\frac{1.6}{2}\)

    = 0.8

    = \(\frac{\text{density of solid}}{\text{density of kerosine}}\)

    = \(\frac{2.4}{0.8}\) = 3

    Reply
    Like