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All the heat generated in a 5 ohms resistor by 2A flowing for 30 seconds is used...


Question

All the heat generated in a 5 ohms resistor by 2A flowing for 30 seconds is used to evaporate 5g of a liquid at its boiling point. Which of the following is the correct value of the specific latent heat of the liquid?

Options

A) 120J

B) 60Jg-1

C) 120Jg-1

D) 1500J

E) 1500Jg-1


The correct answer is C.

Explanation:

Heat energy = Electrical energy

mL = I2RT

5 x L = 2 x 2 x 5 x 30

L = 120Jg-1


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