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In the calibration of an ammeter using faraday's laws of electrolysis, the ammete...


Question

In the calibration of an ammeter using faraday's laws of electrolysis, the ammeter reading is kept constant at 1.2A. If 0.990g of copper is deposited in 40 minutes , the correction to be applied to the ammeter is

Options

A) 0.03A

B) 0.04A

C) 0.05A

D) 0.06A


The correct answer is C.

Explanation:

From faraday's law of electrolysis

M = I t Z
0.990 = I x (40 x 60) x 3.3 x 10-4

\( \implies \frac{0.990}{2400 \times 3.3 \times 10^{-4}} = 1.25A \\\text{Thus the correction to be made } = 1.25 - 1.20 = 0.05A \)


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Dicussion (1)

  • From faraday's law of electrolysis

    M = I t Z
    0.990 = I x (40 x 60) x 3.3 x 10-4

    \( \implies \frac{0.990}{2400 \times 3.3 \times 10^{-4}} = 1.25A \\\text{Thus the correction to be made } = 1.25 - 1.20 = 0.05A \)

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