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# In the calibration of an ammeter using faraday's laws of electrolysis, the ammete...

### Question

In the calibration of an ammeter using faraday's laws of electrolysis, the ammeter reading is kept constant at 1.2A. If 0.990g of copper is deposited in 40 minutes , the correction to be applied to the ammeter is

A) 0.03A

B) 0.04A

C) 0.05A

D) 0.06A

### Explanation:

M = I t Z
0.990 = I x (40 x 60) x 3.3 x 10-4

$$\implies \frac{0.990}{2400 \times 3.3 \times 10^{-4}} = 1.25A \\\text{Thus the correction to be made } = 1.25 - 1.20 = 0.05A$$

## Dicussion (1)

• From faraday's law of electrolysis

M = I t Z
0.990 = I x (40 x 60) x 3.3 x 10-4

$$\implies \frac{0.990}{2400 \times 3.3 \times 10^{-4}} = 1.25A \\\text{Thus the correction to be made } = 1.25 - 1.20 = 0.05A$$