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A bead traveling on a straight wire is brought to rest at 0.2m by friction. If t...


Question

A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1 determine the work done by the friction

Options

A) \( 2 \times 10^{-4}J \)

B) \( 2 \times 10^{-3}J \)

C) \( 2 \times 10^{1}J \)

D) \( 2 \times 10^{2}J \)


The correct answer is B.

Explanation:

Work done by friction = Friction force x Displacement from the relation, f = uR

where u = coefficient of friction; R= Normal reaction

F = u mg (R =mg)
= 0.1 x 0.01 x 10
work done = F x Displacement
= 0.1 x 0.01 x 10 x 0.2
= 0.002 or \( 2 \times 10^{-3}J \)


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Dicussion (1)

  • Work done by friction = Friction force x Displacement from the relation, f = uR

    where u = coefficient of friction; R= Normal reaction

    F = u mg (R =mg)
    = 0.1 x 0.01 x 10
    work done = F x Displacement
    = 0.1 x 0.01 x 10 x 0.2
    = 0.002 or \( 2 \times 10^{-3}J \)

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