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If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of for...


Question

If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?

Options

A) 250N

B) 200N

C) 100N

D) 50N


The correct answer is A.

Explanation:

Original length = 20m
first new length = 20.01m

first increase in length = 20.01m - 20m = 0.01m

Second new length = 20.05m
second increase in length = 20.05 - 20m = 0.05m

From hooke's law = \( \frac{F_1}{e_1} = \frac{F_2}{e_2} \implies \frac{50}{0.01} = \frac{F_2}{0.05} \\
\implies F_2 = \frac{50 \times 0.05}{0.01} = 250N \)


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Dicussion (1)

  • Original length = 20m
    first new length = 20.01m

    first increase in length = 20.01m - 20m = 0.01m

    Second new length = 20.05m
    second increase in length = 20.05 - 20m = 0.05m

    From hooke's law = \( \frac{F_1}{e_1} = \frac{F_2}{e_2} \implies \frac{50}{0.01} = \frac{F_2}{0.05} \\
    \implies F_2 = \frac{50 \times 0.05}{0.01} = 250N \)

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