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Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid ...

Question

Calculate the upthrust on an object of volume 50cm3 which is immersed in liquid of density 103kgm-3 [g = 10ms-2]

Options

A)
0.8N
B)
2.5N
C)
0.5N
D)
1.0N

Related Lesson: Density and Archimedes’ Principle | Fluid Statics

The correct answer is C.

Explanation:

Upthrust = change in weight

density = \(\frac{\text{mass}}{\text{volume}}\)

Mass of liquid displaced = Density of Liquid × Volume;

= 103 × 50 × 10− 6m3

= 0.05kg

(Note that the volume of 50cm3 was converted to m3 by multiplying by 106) i.e 50cm3 = 50 × 10−6m3)

Since mass displaced = 0.05kg

Upthrust = mg = 0.05 × 10

= 0.5N

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  • Nigerian Scholars Follow4 years ago

    Upthrust = change in weight

    density = \(\frac{\text{mass}}{\text{volume}}\)

    Mass of liquid displaced = Density of Liquid × Volume;

    = 103 × 50 × 10− 6m3

    = 0.05kg

    (Note that the volume of 50cm3 was converted to m3 by multiplying by 106) i.e 50cm3 = 50 × 10−6m3)

    Since mass displaced = 0.05kg

    Upthrust = mg = 0.05 × 10

    = 0.5N

    Reply
    7
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