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A simple machine overcomes a load of 4000N when a force of 200N is applied. If t...


Question

A simple machine overcomes a load of 4000N when a force of 200N is applied. If the velocity ration of the machine is 25, calculate the efficiency of the machine?

Options

A) 1.25%

B) 80%

C) 125%

D) 0.8%


The correct answer is B.

Explanation:

first of all list that you r given
load =4000N
effort = 200N
V.R is 25
efficiency of a machine is eff= ma/vr x 100%
M.A is load/effort
which is 4000N/200N =20
so M.A =20
eff=ma/vr x100 %
eff=20/25 x100%
80%

Explanation provided by Anyanwu Prosper


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Dicussion (1)

  • Anyanwu Prosper

    first of all list that you r given
    load =4000N
    effort = 200N
    V.R is 25
    efficiency of a machine is eff= ma/vr x 100%
    M.A is load/effort
    which is 4000N/200N =20
    so M.A =20
    eff=ma/vr x100 %
    eff=20/25 x100%
    80%