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The probability that a side will win/draw is divided in three

A win , a loss , a draw

A draw will be one out of the three outcomes

Therefore its 1/3

In a football game, one team either wins or there is a tie. This means there are three possible outcomes: a win, a loss or a draw. Therefore, the probability of a draw is \(\frac{1}{3}\).

The given answer is incorrect. There are three possibilities: a win, a loss or a draw. So, the possibility of a draw is \(\frac{1}{3}\).

\(P\) (games end in draw)

\(\Rightarrow\) Team \(P\) wins and \(Q\) wins

\(P\) (\(P\) wins) \(= \frac{1}{2}\)

\(P\) (\(Q\) wins) \(= \frac{1}{2}\)

Therefore, \(P\) (games ends in draw) \(= \frac{1}{2} \times \frac{1}{2} = \frac{1}{4}\)

Wrong