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IN the diagram above, TPS is a straight line, PQRS is a parallelogram with base ...


Question

IN the diagram above, TPS is a straight line, PQRS is a parallelogram with base QR and height 8cm. |QR| = 6cm and the area of triangle QST is 52cm2. Find the area of ΔQPT.

Options

A) 39cm2

B) 28cm2

C) 24cm2

D) 21cm2

E) 19cm2

The correct answer is B.

Explanation:

Area of \(\Delta\)QST = 52 2; height = 8cm
b=base length; but A = 1/2b x h
=52=1/2 x b x 8cm = 104 =86
b=104/8 = 13cm; ST= 13cm; PS = 6cm
TP = 13 - 6 = 7cm;
area of \(\Delta\)QST = 1/2 b x h
= 1/2 x 7 x 8/1 = 28cm 2

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Dicussion (1)

  • Area of \(\Delta\)QST = 52 2; height = 8cm
    b=base length; but A = 1/2b x h
    =52=1/2 x b x 8cm = 104 =86
    b=104/8 = 13cm; ST= 13cm; PS = 6cm
    TP = 13 - 6 = 7cm;
    area of \(\Delta\)QST = 1/2 b x h
    = 1/2 x 7 x 8/1 = 28cm 2

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