Home » Past Questions » Mathematics » In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD....

In ΔABC above, BC is produced to D, /AB/ = /AC/ and ∠BAC = 50o. Find ∠ACD....



Dicussion (1)

  • ACB = ABC [Base angles of isoceles triangle]
    ACB + ABC + 50o = 180o[sum of angles in a triangle]
    ACB + ABC = 180o - 50o = 130o

    ACB
    130o/2
    = 65o

    ACD + ACB = 180o[sum of ∠s on a straight line]
    ACD + 65o = 180o
    ACD = 180o - 65o = 115o

    Reply
    Like