Home » Past Questions » Mathematics » In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of...

In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of...


Question

In the diagram, DE||BC, |AD| = x cm and |DB| = |AE| = ycm. Find |CE| in terms of x and y.

Options

A) x

B) \(\frac{x^2}{y}\)

C) \(\frac{y}{x^2}\)

D) \(\frac{y^2}{x}\)

The correct answer is D.

Explanation:

\(\frac{x}{x+y}=\frac{y}{x+CE}\\xy + xCE = xy + y^2\\∴xCE = y^2\\CE=\frac{y^2}{x}\)

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