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For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\)


Question

For what values of y is the expression \(\frac{6y-1}{y^2 - y-6}\)

Options

A) \(\frac{1}{6}, \frac{1}{4}\)

B) 3, -2

C) -3, 2

D) 0,1

The correct answer is B.

Explanation:

The expression is not defines when y2 - y - 6 = 0
=> y2 - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2

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