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# For what values of y is the expression $$\frac{6y-1}{y^2 - y-6}$$

### Question

For what values of y is the expression $$\frac{6y-1}{y^2 - y-6}$$

### Options

A) $$\frac{1}{6}, \frac{1}{4}$$

B) 3, -2

C) -3, 2

D) 0,1

### Explanation:

The expression is not defines when y2 - y - 6 = 0
=> y2 - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2

## Dicussion (1)

• The expression is not defines when y2 - y - 6 = 0
=> y2 - 3y + 2y - 6 = 0 => (y-3)(y+2) = 0 => y
-3 = 0 or y + 2 = 0 => y = 3 or -2