Home » Past Questions » Mathematics » In the diagram, |QR| = 5cm, PQR = 60o and PSR = 45o. Find |PS|, leaving your ans...

In the diagram, |QR| = 5cm, PQR = 60o and PSR = 45o. Find |PS|, leaving your ans...



Dicussion (1)

  • tan 6o = \(\frac{|PR|}{|QR|}\)

    \(\sqrt{3} = \frac{|PR|}{5}\)

    = |PR| = \(5 \sqrt{3}\)cm

    sin 45 = \(\frac{|PR|}{|PS|}\)

    \(\frac{1}{\sqrt{2}}\) = \(\frac{5 \sqrt{3}}{|PS|}\)

    |PS| = \(5 \sqrt{3}\) x \(\sqrt{2}\)

    = 5\(\sqrt{6}\)cm

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