Home » Past Questions » Mathematics » In the diagram |LN| = 4cm, LNM = 90o and tan y = \(\frac{2}{3}\). What is the ar...

In the diagram |LN| = 4cm, LNM = 90o and tan y = \(\frac{2}{3}\). What is the ar...



Dicussion (1)

  • Since tan y = \(\frac{2}{3}\) and LN = 4

    tan y = \(\frac{2 \times 4}{3 \times 4} = \frac{8}{12} = \frac{4}{6}\)

    then tan y = \(\frac{opp}{adj}\)

    MN = 6cm

    Area of angle LMN = \(\frac{1}{2}\)bh

    = \(\frac{1}{2} \times 6 \times 4\)

    = 12cm3

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