Home » Past Questions » Mathematics » In the diagram, <QPR = 60o, <PQR = 50o, <QRS = 2xo, <SRP = 3xo, <...

In the diagram, <QPR = 60o, <PQR = 50o, <QRS = 2xo, <SRP = 3xo, <...



Dicussion (1)

  • < RQT = < QRS = 2x (Alternate angles). But in \(\bigtriangleup\) PRQ

    50 + 60 + (2x + 3x) = 180o(Angles in a triangle)

    110 + 5x = 180o

    5x = 180o - 110 = 70o

    x = \(\frac{70}{5}\) = 14o

    Also y + 50 + 2(14) = 180o

    y + 50 + 28 = 180o

    y = 180 - 78

    y = 102o

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