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# If p-2g + 1 = g + 3p and p - 2 = 0, find g

### Question

If p-2g + 1 = g + 3p and p - 2 = 0, find g

A) -2

B) -1

C) 1

D) 2

### Explanation:

p - 2g + 1 = g + 3p.........(1)

p - 2 = 0 .........(2)

From (2), p = 2; put p = 2 into (1);

2 - 2g + 1 = g + 3(2)

3 - 2g = g + 6

-2g - g = 6 - 3

-3g = 3

g = $$\frac{3}{-3}$$

g = -1

## Dicussion (1)

• p - 2g + 1 = g + 3p.........(1)

p - 2 = 0 .........(2)

From (2), p = 2; put p = 2 into (1);

2 - 2g + 1 = g + 3(2)

3 - 2g = g + 6

-2g - g = 6 - 3

-3g = 3

g = $$\frac{3}{-3}$$

g = -1