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In the diagram, QR//ST, /PQ/ = /PR/ and < PST = 75o. Find the value of y....



Dicussion (1)

  • In \(\bigtriangleup\) PQR,

    Q = S = 75o (Corresponding angle)

    R = Q = 75o (Base angles of an isosceles \(\bigtriangleup\))

    But, y + 75o = 180o (Sum of angles in a straight line)

    y = 180 - 75

    y = 105o

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