Home » Past Questions » Mathematics » In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\)...

In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\)...


Question

In the diagram, O is the centre, \(\bar{RT}\) is a diameter, < PQT = 33\(^o\) and < TOS =  76\(^o\). Using the diagram, find the size of angle PRS.

Options

A) 76o

B) 71o

C) 38o

D) 33o

The correct answer is B.

Explanation:

In the diagram,  < TRS = \(\frac{76^o}{2}\) = 38\(^o\)

Hence, angle PRS = 33\(^o\) + 38\(^o\)

= 71\(^o\)


More Past Questions:


Dicussion (1)