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Two perpendicular lines PQ and QR intersect at (1, -1), if the equation of PQ is...



Dicussion (1)

  • Ogunbayo Roqeebat

    x-2y+4=0
    -2y=-x-4
    y=x/2+2
    But, m1m2=-1
    m2=-1/m1
    When m1=1/2
    m2=-1/(1/2)
    m2=-2
    The equation of QR;
    y=mx+c
    the intersection is(1,-1)
    y=mx+c
    -1=1X(-2)+c
    -1=-2+c
    c=1
    y=-2x+1
    2x+y-1=0