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The formula for calculating the volume of frustum= V=1 / 3(a^2+ab+b^2)h

a=3,b=6,h=5

Sub everything inside the formula and it will give u 105

Formula for the frustum of a pyramid=⅓h ( a² + ab + b² )

Where a ( base ) = 6

Where b ( top ) = 3 and the height, h = 5.

⅓ × 5 ( 6² + 6×3 + 3² ) = 105cm³.

The formular is

V=h/3(A+A'+√AA'

Where V is volume

H is height

A is area of upper base

A' area of lower base

Since the frsutum is a square

The area of upper base is A^2

Which is 3×3=9

Area of the bottom also square is

6×6=36

Height =5cm (given)

We have V =5/3(9+36+√(9×36)

V=5/3(45+√324

V=5/3(45 +18)

V=5/3(63)

V=315/3

V=105cm^3