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Evaluate ∫sec2θ dθ



Dicussion (1)

  • ∫sec2θ dθ = ∫ 1/cos2
    ∫(cos)-2 dθ,
    let u = cos θ
    ∴∫u-2 = 1/u + c
    ∫cos θ = sin θ + c
    ∫sec-2θ = 1/u sin θ + c
    = (sinθ / cosθ) + c
    = Tan θ + c

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