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Evaluate \(\int_1 ^2(6x^2-2x)dx\)


Question

Evaluate \(\int_1 ^2(6x^2-2x)dx\)

Options

A) 16

B) 13

C) 12

D) 11

The correct answer is D.

Explanation:

\(\int_1 ^2(6x^2-2x)dx=[\frac{6x^3}{3}-\frac{2x^2}{2}]_1 ^2\\= [2x^3 - x^2]_1^2\)
= [2(2)3 - (2)2] – [2(1)3 - (1)2]
= [16-4] – [2-1]
= 12 – 1
= 11

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