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Find the derivative of y = sin(2x3 + 3x - 4)



Dicussion (1)

  • y = sin (2x3 + 3x - 4)
    let u = 2x3 + 3x - 4
    ∴du/dx = 6x2
    y = sin U
    dy/du = cos U
    dy/dx = du/dx * dy/dy
    ∴dy/dx = (6x2 + 3) cos U
    = (6x2 + 3)cos(2x3 + 3x - 4)

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