The quadratic equation whose roots are \((x-3)\) and \(\left(x+\frac 1 3\right)\) ...
Question
The quadratic equation whose roots are \((x-3)\) and \(\left(x+\frac 1 3\right)\) isOptions
A) \(x^2+\frac 8 3x-1=0\)
B) \(x^2-2x-3=0\)
C) \(x^2-\frac 8 3x-1=0\)
D) \(x^2-3=0\)
The correct answer is C.
Explanation:
\((x-3)\left( x+\frac{1}{3} \right) = x^2+\frac{1}{3}x-3x=0\)
\(x^2-\frac{8}{3}x-1=0\)
\(x^2-\frac{8}{3}x-1=0\)
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\((x-3)\left( x+\frac{1}{3} \right) = x^2+\frac{1}{3}x-3x=0\)
\(x^2-\frac{8}{3}x-1=0\)