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# The quadratic equation whose roots are $$(x-3)$$ and $$\left(x+\frac 1 3\right)$$ ...

### Question

The quadratic equation whose roots are $$(x-3)$$ and $$\left(x+\frac 1 3\right)$$ is

### Options

A) $$x^2+\frac 8 3x-1=0$$

B) $$x^2-2x-3=0$$

C) $$x^2-\frac 8 3x-1=0$$

D) $$x^2-3=0$$

### Explanation:

$$(x-3)\left( x+\frac{1}{3} \right) = x^2+\frac{1}{3}x-3x=0$$
$$x^2-\frac{8}{3}x-1=0$$

## Dicussion (1)

• $$(x-3)\left( x+\frac{1}{3} \right) = x^2+\frac{1}{3}x-3x=0$$
$$x^2-\frac{8}{3}x-1=0$$