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If 0.0000152 x 0.042 = A x 108, where 1 \(\leq\) A < 10, find A and B....



Dicussion (1)

  • 0.0000152 x 0.042 = A x 108
    1 \(\leq\) A < 10, it means values of A includes 1 - 9

    0.0000152 = 1.52 x 10-5
    0.00042 = 4.2 x 10-4
    1.52 x 4.2 = 6.384
    10-5 x 10-4
    = 10-5-4
    = 10-9
    = 6.38 x 10-9
    A = 6.38, B = -9

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