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If 0.0000152 x 0.042 = A x 108, where 1 \(\leq\) A < 10, find A and B....


Question

If 0.0000152 x 0.042 = A x 108, where 1 \(\leq\) A < 10, find A and B.

Options

A)
A = 9, B = 6.38
B)
A = 6.38, B = -9
C)
A = -6.38, B = -9
D)
A = -9, B = -6.38

The correct answer is B.

Explanation:

0.0000152 x 0.042 = A x 108
1 \(\leq\) A < 10, it means values of A includes 1 - 9

0.0000152 = 1.52 x 10-5
0.00042 = 4.2 x 10-4
1.52 x 4.2 = 6.384
10-5 x 10-4
= 10-5-4
= 10-9
= 6.38 x 10-9
A = 6.38, B = -9


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Dicussion (1)

  • 0.0000152 x 0.042 = A x 108
    1 \(\leq\) A < 10, it means values of A includes 1 - 9

    0.0000152 = 1.52 x 10-5
    0.00042 = 4.2 x 10-4
    1.52 x 4.2 = 6.384
    10-5 x 10-4
    = 10-5-4
    = 10-9
    = 6.38 x 10-9
    A = 6.38, B = -9

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