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From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point ...


Question

From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.

Options

A) 0.30o

B) 045o

C) 060o

D) 090o

The correct answer is C.

Explanation:

tan \(\theta\) = \(\frac{60\sqrt{3}}{60}\) = \(\sqrt{3}\)
\(\theta\) = tan \(\frac{1}{3}\) = 60o
Bearing of y from x = 060o

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