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# From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point ...

### Question

From a point Z, 60 m north of X, a man walks 60√3m eastwards to another point Y. Find the bearing of Y from X.

A) 0.30o

B) 045o

C) 060o

D) 090o

### Explanation:

tan $$\theta$$ = $$\frac{60\sqrt{3}}{60}$$ = $$\sqrt{3}$$
$$\theta$$ = tan $$\frac{1}{3}$$ = 60o
Bearing of y from x = 060o

## Dicussion (1)

• tan $$\theta$$ = $$\frac{60\sqrt{3}}{60}$$ = $$\sqrt{3}$$
$$\theta$$ = tan $$\frac{1}{3}$$ = 60o
Bearing of y from x = 060o