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Obtain a maximum value of the function f(x) x3 - 12x + 11



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  • f(x) = x3 - 12x + 11
    \(\frac{df(x)}{dx)}\) = 3x2 - 12 = 0
    ∴ 3x2 - 12 = 0 \(\to\) x2m = 4
    x = \(\pm\)2, f(+2) = 8 - 24 + 11 = -15
    = f(-2) = (-8) + 24 + 11
    = 35 - 8 = 27
    ∴ maximum value = 27

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