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The angle of depression of a boat from the top of a cliff 10m high is 30. How fa...


Question

The angle of depression of a boat from the top of a cliff 10m high is 30. How far is the boat from the foot of the cliff?

Options

A) \(\frac{5√3m}{3}\)

B) 5√3m

C) 10√3m

D) \(\frac{10√3m}{3}\)

The correct answer is C.

Explanation:

RQP = 90o
PQS = 30o but
RQS = 90o = \(\frac{RS}{10}\)
RS = 10 tan 60o
RS = 10 tan 60o
RS = 10√3m

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