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Differentiate \(\frac{x}{cosx}\) with respect to x


Question

Differentiate \(\frac{x}{cosx}\) with respect to x

Options

A) 1 + x sec x tan x

B) 1 + sec2 x

C) cos x + x tan x

D) x sec x tan x + secx

The correct answer is D.

Explanation:

let y = \(\frac{x}{cosx}\) = x sec x
y = u(x) v (x0
\(\frac{dy}{dx}\) = U\(\frac{dy}{dx}\) + V\(\frac{du}{dx}\)
dy x [secx tanx] + secx
x = x secx tanx + secx

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Dicussion (1)

  • let y = \(\frac{x}{cosx}\) = x sec x
    y = u(x) v (x0
    \(\frac{dy}{dx}\) = U\(\frac{dy}{dx}\) + V\(\frac{du}{dx}\)
    dy x [secx tanx] + secx
    x = x secx tanx + secx

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